What is the integral from 0 to 6 of 1/x ?

The integral from 0 to 6 of 1/x is diverges

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integral from 0 to 6 of 1/x

\int_{0}^{6} \frac{1}{x} d x

diverges

Solution steps

\int_{0}^{6} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{0}^{6}

Compute the boundaries:

diverges

= diverges

\int_{1}^{2} \frac{x + 4}{x} d x

\int_{0}^{\frac{π}{2}} x \cdot cos (3 x) d x

\int_{- 5}^{0} ∣ x + 2 ∣ d x

\int_{0}^{2} 4^{5 x} d x

\int_{2}^{4} x^{2} - 7 x + 10 d x

What is the integral from 0 to 6 of 1/x ?
The integral from 0 to 6 of 1/x is diverges