What is the integral from 0 to 2 of 8^x ?

The integral from 0 to 2 of 8^x is (21)/(ln(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2 of 8^x

\int_{0}^{2} 8^{x} d x

\frac{21}{ln ( 2 )}

Solution steps

\int_{0}^{2} 8^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{8 ^{x}}{ln ( 8 )}]_{0}^{2}

Simplify

ln (8) : 3 ln (2)

= [\frac{8 ^{x}}{3 ln ( 2 )}]_{0}^{2}

Compute the boundaries:

\frac{21}{ln ( 2 )}

= \frac{21}{ln ( 2 )}

\int_{0}^{2} \frac{40}{x ^{2} + 4} d x

\int_{9}^{x^{3}} \frac{1}{p ^{2}} d p

\int_{0}^{4} t^{3} d t

\int_{- 2}^{4} \frac{y + 4}{2} - \frac{y ^{2}}{4} d y

\int_{0}^{c o s (θ)} cos (y) d y

What is the integral from 0 to 2 of 8^x ?
The integral from 0 to 2 of 8^x is (21)/(ln(2))