What is the integral from 0 to pi of (9sin(x)) ?

The integral from 0 to pi of (9sin(x)) is 18

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integral from 0 to pi of (9sin(x))

\int_{0}^{π} (9 sin (x)) d x

18

Solution steps

\int_{0}^{π} 9 sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int_{0}^{π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= 9 [- cos (x)]_{0}^{π}

Compute the boundaries:

2

= 9 \cdot 2

Simplify

= 18

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What is the integral from 0 to pi of (9sin(x)) ?
The integral from 0 to pi of (9sin(x)) is 18