What is the integral from 0 to ln(x) of e^y ?

The integral from 0 to ln(x) of e^y is x-1

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integral from 0 to ln(x) of e^y

\int_{0}^{l n (x)} e^{y} d y

x - 1

Solution steps

\int_{0}^{l n (x)} e^{y} d y

Use the common integral:

\int e^{y} d y = e^{y}

= [e^{y}]_{0}^{l n (x)}

Compute the boundaries:

x - 1

= x - 1

\int_{1}^{2} x 2^{x^{2}} d x

\int_{0}^{1} 2 + x^{\frac{1}{3}} d x

\int_{0}^{π} \frac{sin ( x )}{2} d x

\int_{2 π}^{3 π} x sin (x) d x

\int_{1}^{0} (e^{x} + e^{- 3}) d x

What is the integral from 0 to ln(x) of e^y ?
The integral from 0 to ln(x) of e^y is x-1