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Popular >

integral from 1 to 2 of (4-x)

Solution

\int_{1}^{2} (4 - x) d x

Solution

\frac{5}{2}

+1

Solution steps

\int_{1}^{2} 4 - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 4 d x - \int_{1}^{2} x d x

\int_{1}^{2} 4 d x = 4

\int_{1}^{2} x d x = \frac{3}{2}

= 4 - \frac{3}{2}

Simplify

4 - \frac{3}{2} : \frac{5}{2}

= \frac{5}{2}

Popular Examples

integral from 0 to t^2 of sqrt(u^7)

\int_{0}^{t^{2}} u^{7} d u

integral from 1 to 2 of ((x^2+2x+4))/x

\int_{1}^{2} \frac{( x ^{2} + 2 x + 4 )}{x} d x

integral from 4 to 6 of xln(x/6)

\int_{4}^{6} x ln (\frac{x}{6}) d x

integral from 2 to-2 of x^2-4

\int_{2}^{- 2} x^{2} - 4 d x

integral from-1 to 0 of-x^3

\int_{- 1}^{0} - x^{3} d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (4-x) ?
The integral from 1 to 2 of (4-x) is 5/2