What is the integral from-1 to 0 of-x^3 ?

The integral from-1 to 0 of-x^3 is 1/4

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integral from-1 to 0 of-x^3

\int_{- 1}^{0} - x^{3} d x

\frac{1}{4}

Decimal Notation

0.25

Solution steps

\int_{- 1}^{0} - x^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{- 1}^{0} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{- 1}^{0}

= - [\frac{x ^{4}}{4}]_{- 1}^{0}

Compute the boundaries:

- \frac{1}{4}

= - (- \frac{1}{4})

Simplify

= \frac{1}{4}

\int_{0}^{1} f (1 - x) d x

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\int_{0}^{1} (- 1 - x^{2}) d x

\int_{1}^{4} \frac{3}{1 + 4 x ^{2}} d x

What is the integral from-1 to 0 of-x^3 ?
The integral from-1 to 0 of-x^3 is 1/4