What is the integral from-pi/2 to pi/2 of-sin(x) ?

The integral from-pi/2 to pi/2 of-sin(x) is 0

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integral from-pi/2 to pi/2 of-sin(x)

\int_{- \frac{π}{2}}^{\frac{π}{2}} - sin (x) d x

0

Solution steps

\int_{- \frac{π}{2}}^{\frac{π}{2}} - sin (x) d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

- sin (x) :

Odd

= 0

\int_{0}^{1} (8 x + x) d x

\int_{3}^{x^{2}} ln (t) d t

\int_{0}^{4} \frac{1}{2} d x

\int_{1}^{x} x^{3} d x

\int_{0}^{L} sin^{2} (\frac{3 π x}{L}) d x

What is the integral from-pi/2 to pi/2 of-sin(x) ?
The integral from-pi/2 to pi/2 of-sin(x) is 0