What is (\partial)/(\partial y)(sqrt(2x-3y)) ?

The answer to (\partial)/(\partial y)(sqrt(2x-3y)) is -3/(2sqrt(2x-3y))

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(\partial)/(\partial y)(sqrt(2x-3y))

\frac{\partial}{\partial y} (2 x - 3 y)

- \frac{3}{2 2 x - 3 y}

Solution steps

\frac{\partial}{\partial y} (2 x - 3 y)

Treat

x

as a constant

Apply the chain rule:

\frac{1}{2 2 x - 3 y} \frac{\partial}{\partial y} (2 x - 3 y)

= \frac{1}{2 2 x - 3 y} \frac{\partial}{\partial y} (2 x - 3 y)

\frac{\partial}{\partial y} (2 x - 3 y) = - 3

= \frac{1}{2 2 x - 3 y} (- 3)

Simplify

\frac{1}{2 2 x - 3 y} (- 3) : - \frac{3}{2 2 x - 3 y}

= - \frac{3}{2 2 x - 3 y}

\frac{d}{d x} ((2 tan^{2} (2 x) - 1)^{\frac{1}{2}})

\frac{d}{d u} (u^{2} + v^{2})

n = 1 \sum \infty \frac{( - 3 ) ^{n}}{7 ^{n + 1}}

\int 8 (y^{4} + 4 y^{2} + 1)^{2} (y^{3} + 2 y) d y

y^{^{'}} + 3 (1 + x^{2}) y = 0

What is (\partial)/(\partial y)(sqrt(2x-3y)) ?
The answer to (\partial)/(\partial y)(sqrt(2x-3y)) is -3/(2sqrt(2x-3y))