What is the integral from-pi to 0 of 2x ?

The integral from-pi to 0 of 2x is -pi^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-pi to 0 of 2x

\int_{- π}^{0} 2 x d x

- π^{2}

Decimal Notation

- 9.86960 \dots

Solution steps

\int_{- π}^{0} 2 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{- π}^{0} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{- π}^{0}

= 2 [\frac{x ^{2}}{2}]_{- π}^{0}

Compute the boundaries:

- \frac{π ^{2}}{2}

= 2 (- \frac{π ^{2}}{2})

Simplify

= - π^{2}

\int_{- 1}^{0} 1 - 3 x d x

\int_{- 1}^{0} x^{2} (x + 1)^{\frac{1}{2}} d x

\int_{- π}^{0} x^{2} cos (n x) d x

\int_{0}^{1} g (x) d x

\int_{1}^{4} x - 2 d x

What is the integral from-pi to 0 of 2x ?
The integral from-pi to 0 of 2x is -pi^2