What is the integral from 0 to 3 of (xe^x) ?

The integral from 0 to 3 of (xe^x) is 2e^3+1

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integral from 0 to 3 of (xe^x)

\int_{0}^{3} (x e^{x}) d x

2 e^{3} + 1

Decimal

41.17107 \dots

Solution steps

\int_{0}^{3} x e^{x} d x

Apply Integration By Parts

: [e^{x} x - \int e^{x} d x]_{0}^{3}

= [e^{x} x - \int e^{x} d x]_{0}^{3}

\int e^{x} d x = e^{x}

= [e^{x} x - e^{x}]_{0}^{3}

Compute the boundaries:

2 e^{3} + 1

= 2 e^{3} + 1

\int_{0}^{\frac{π}{2}} (e^{x} - cos (x)) d x

\int_{- 2}^{0} (x^{2} - x) d x

\int_{- 1}^{1} x^{2} + 6 x + 2 d x

\int_{1}^{3} 95 + 972 x^{2} - 18 x d x

\int_{1}^{0} 2 x + 3 d x

What is the integral from 0 to 3 of (xe^x) ?
The integral from 0 to 3 of (xe^x) is 2e^3+1