What is the integral from 1 to 4 of sqrt(7/x) ?

The integral from 1 to 4 of sqrt(7/x) is 2sqrt(7)

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integral from 1 to 4 of sqrt(7/x)

\int_{1}^{4} \frac{7}{x} d x

27

Decimal Notation

5.29150 \dots

Solution steps

\int_{1}^{4} \frac{7}{x} d x

Apply Integration By Parts

: [\frac{7}{x} x - \int - \frac{7}{2 x ^{\frac{1}{2}}} d x]_{1}^{4}

= [\frac{7}{x} x - \int - \frac{7}{2 x ^{\frac{1}{2}}} d x]_{1}^{4}

\int - \frac{7}{2 x ^{\frac{1}{2}}} d x = - 7 x

= [\frac{7}{x} x - (- 7 x)]_{1}^{4}

Simplify

= [\frac{7}{x} x + 7 x]_{1}^{4}

Compute the boundaries:

27

= 27

\frac{60 t ^{2}}{t ^{2} + 150}

\frac{\partial}{\partial x} (8 x y - \frac{1}{4} (x + y)^{4})

\frac{d}{d x} (cos (\frac{π}{x}))

\int_{2}^{\infty} - 8 x^{- 2} d x

x \to 0 lim (\frac{cos ( 3 x )}{x})

What is the integral from 1 to 4 of sqrt(7/x) ?
The integral from 1 to 4 of sqrt(7/x) is 2sqrt(7)