What is the integral from 2 to infinity of-8x^{-2} ?

The integral from 2 to infinity of-8x^{-2} is -4

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integral from 2 to infinity of-8x^{-2}

\int_{2}^{\infty} - 8 x^{- 2} d x

- 4

Solution steps

\int_{2}^{\infty} - 8 x^{- 2} d x

Compute the indefinite integral:

\int - 8 x^{- 2} d x = \frac{8}{x} + C

Compute the boundaries:

\int_{2}^{\infty} - 8 x^{- 2} d x = 0 - 4

= 0 - 4

Simplify

= - 4

x \to 0 lim (\frac{cos ( 3 x )}{x})

\frac{d}{d x} (e^{- x} cos (x))

\frac{d y}{d x} = \frac{y ^{2} + 1}{x ^{2} + 1}

y = cos (tan (x))

\frac{\partial}{\partial x} (x^{2} - 2 y)

What is the integral from 2 to infinity of-8x^{-2} ?
The integral from 2 to infinity of-8x^{-2} is -4