What is the solution for (dy)/(dx)=(y^2+1)/(x^2+1) ?

The solution for (dy)/(dx)=(y^2+1)/(x^2+1) is y=tan(arctan(x)+c_{1})

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=(y^2+1)/(x^2+1)

\frac{d y}{d x} = \frac{y ^{2} + 1}{x ^{2} + 1}

y = tan (arctan (x) + c_{1})

Solution steps

\frac{d y}{d x} = \frac{y ^{2} + 1}{x ^{2} + 1}

Solve separable ODE:

y = tan (arctan (x) + c_{1})

y = tan (arctan (x) + c_{1})

y = cos (tan (x))

\frac{\partial}{\partial x} (x^{2} - 2 y)

\frac{4}{x}, 16 x, \frac{1}{16} x

\int x^{2} x + 4 d x

\int \frac{sin ( 2 x )}{1 + cos ^{2} ( x )} d x

What is the solution for (dy)/(dx)=(y^2+1)/(x^2+1) ?
The solution for (dy)/(dx)=(y^2+1)/(x^2+1) is y=tan(arctan(x)+c_{1})