What is the integral from 3 to 4 of (10)/(9x^2) ?

The integral from 3 to 4 of (10)/(9x^2) is 5/54

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integral from 3 to 4 of (10)/(9x^2)

\int_{3}^{4} \frac{10}{9 x ^{2}} d x

\frac{5}{54}

Decimal

0.09259 \dots

Solution steps

\int_{3}^{4} \frac{10}{9 x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{10}{9} \cdot \int_{3}^{4} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{3}^{4}

= \frac{10}{9} [- \frac{1}{x}]_{3}^{4}

Compute the boundaries:

\frac{1}{12}

= \frac{10}{9} \cdot \frac{1}{12}

Simplify

= \frac{5}{54}

\int_{0}^{2} (x - ∣ x - 1 ∣) d x

\int_{0}^{\infty} cos (m) x d x

\int_{0}^{2} 4^{4 x} d x

\int_{0}^{1} (x + 4)^{10} d x

\int_{- 1}^{1} \frac{1}{x ^{4}} + \frac{1}{x - 4} d x

What is the integral from 3 to 4 of (10)/(9x^2) ?
The integral from 3 to 4 of (10)/(9x^2) is 5/54