What is the integral from-1 to 1 of (\sqrt[3]{x}-9) ?

The integral from-1 to 1 of (\sqrt[3]{x}-9) is -18

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integral from-1 to 1 of (\sqrt[3]{x}-9)

\int_{- 1}^{1} (3 x - 9) d x

- 18

Solution steps

\int_{- 1}^{1} 3 x - 9 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 3 x d x - \int_{- 1}^{1} 9 d x

\int_{- 1}^{1} 3 x d x = 0

\int_{- 1}^{1} 9 d x = 18

= 0 - 18

Simplify

= - 18

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What is the integral from-1 to 1 of (\sqrt[3]{x}-9) ?
The integral from-1 to 1 of (\sqrt[3]{x}-9) is -18