What is the integral from 4 to x of (64)/(t^5) ?

The integral from 4 to x of (64)/(t^5) is 64(-1/(4x^4)+1/1024)

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integral from 4 to x of (64)/(t^5)

\int_{4}^{x} \frac{64}{t ^{5}} d t

64 (- \frac{1}{4 x ^{4}} + \frac{1}{1024})

Solution steps

\int_{4}^{x} \frac{64}{t ^{5}} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 64 \cdot \int_{4}^{x} \frac{1}{t ^{5}} d t

Apply the Power Rule

: [- \frac{1}{4 t ^{4}}]_{4}^{x}

= 64 [- \frac{1}{4 t ^{4}}]_{4}^{x}

Compute the boundaries:

- \frac{1}{4 x ^{4}} + \frac{1}{1024}

= 64 (- \frac{1}{4 x ^{4}} + \frac{1}{1024})

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What is the integral from 4 to x of (64)/(t^5) ?
The integral from 4 to x of (64)/(t^5) is 64(-1/(4x^4)+1/1024)