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Popular >

integral from 0 to 4 of (x-1)

Solution

\int_{0}^{4} (x - 1) d x

Solution

4

Solution steps

\int_{0}^{4} x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} x d x - \int_{0}^{4} 1 d x

\int_{0}^{4} x d x = 8

\int_{0}^{4} 1 d x = 4

= 8 - 4

Simplify

= 4

Graph

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\int_{0}^{3} (x^{2})^{2} d x

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\int_{- 2}^{3} (3 x^{4} - 5 x^{3} - x - 6) d x

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\int_{0}^{1} x \cdot 1 + x^{2} d x

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\int_{1}^{2} (- x^{2} + 5) d x

integral from 0 to 1 of (2x^3)/(x^2+x)

\int_{0}^{1} \frac{2 x ^{3}}{x ^{2} + x} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of (x-1) ?
The integral from 0 to 4 of (x-1) is 4