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Popular >

integral from 1 to 3 of (x^2+9)

Solution

\int_{1}^{3} (x^{2} + 9) d x

Solution

\frac{80}{3}

+1

Decimal

26.66666 \dots

Solution steps

\int_{1}^{3} x^{2} + 9 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} x^{2} d x + \int_{1}^{3} 9 d x

\int_{1}^{3} x^{2} d x = \frac{26}{3}

\int_{1}^{3} 9 d x = 18

= \frac{26}{3} + 18

Simplify

\frac{26}{3} + 18 : \frac{80}{3}

= \frac{80}{3}

Graph

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\int_{0}^{\frac{π}{2}} 15 sin^{2} (x) d x

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\int_{0}^{x} arcsin (t) d t

integral from 2 to 3 of-3/(x^2)

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Frequently Asked Questions (FAQ)

What is the integral from 1 to 3 of (x^2+9) ?
The integral from 1 to 3 of (x^2+9) is 80/3