What is the integral from 2 to 3 of-3/(x^2) ?

The integral from 2 to 3 of-3/(x^2) is -1/2

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integral from 2 to 3 of-3/(x^2)

\int_{2}^{3} - \frac{3}{x ^{2}} d x

- \frac{1}{2}

Decimal

- 0.5

Solution steps

\int_{2}^{3} - \frac{3}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 3 \cdot \int_{2}^{3} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{2}^{3}

= - 3 [- \frac{1}{x}]_{2}^{3}

Compute the boundaries:

\frac{1}{6}

= - 3 \cdot \frac{1}{6}

Simplify

= - \frac{1}{2}

\int_{1}^{2} (x^{3} + 4) d x

\int_{0}^{1} 3 x^{2} (4 x^{3} - 5)^{3} d x

\int_{0}^{3} (x^{2} + 1)^{2} d x

\int_{1}^{e} \frac{x ^{2} + 1}{2 x} d x

\int_{0}^{7} 4 d x

What is the integral from 2 to 3 of-3/(x^2) ?
The integral from 2 to 3 of-3/(x^2) is -1/2