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Popular >

integral from 1 to 2 of (x^3+4)

Solution

\int_{1}^{2} (x^{3} + 4) d x

Solution

\frac{31}{4}

+1

Decimal

7.75

Solution steps

\int_{1}^{2} x^{3} + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x^{3} d x + \int_{1}^{2} 4 d x

\int_{1}^{2} x^{3} d x = \frac{15}{4}

\int_{1}^{2} 4 d x = 4

= \frac{15}{4} + 4

Simplify

\frac{15}{4} + 4 : \frac{31}{4}

= \frac{31}{4}

Graph

Popular Examples

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\int_{0}^{1} 3 x^{2} (4 x^{3} - 5)^{3} d x

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\int_{0}^{3} (x^{2} + 1)^{2} d x

integral from 1 to e of (x^2+1)/(2x)

\int_{1}^{e} \frac{x ^{2} + 1}{2 x} d x

integral from 0 to 7 of 4

\int_{0}^{7} 4 d x

integral from 0 to infinity of e^{-1x}

\int_{0}^{\infty} e^{- 1 x} d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (x^3+4) ?
The integral from 1 to 2 of (x^3+4) is 31/4