What is the integral from 1 to 5 of-5/(x^2) ?

The integral from 1 to 5 of-5/(x^2) is -4

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integral from 1 to 5 of-5/(x^2)

\int_{1}^{5} - \frac{5}{x ^{2}} d x

- 4

Solution steps

\int_{1}^{5} - \frac{5}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 5 \cdot \int_{1}^{5} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{5}

= - 5 [- \frac{1}{x}]_{1}^{5}

Compute the boundaries:

\frac{4}{5}

= - 5 \cdot \frac{4}{5}

Simplify

= - 4

\int_{0}^{0.05} 250 x d x

\int_{- 4}^{12} x + 4 d x

\int_{- 1}^{0} x^{\frac{1}{5}} - x d x

\int_{- 4}^{1} 1 d x

\int_{0}^{\infty} x e^{- y} d y

What is the integral from 1 to 5 of-5/(x^2) ?
The integral from 1 to 5 of-5/(x^2) is -4