What is the integral from 0 to e of inx ?

The integral from 0 to e of inx is (e^2in)/2

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integral from 0 to e of inx

\int_{0}^{e} in x d x

\frac{e ^{2} in}{2}

Solution steps

\int_{0}^{e} in x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= in \cdot \int_{0}^{e} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{e}

= in [\frac{x ^{2}}{2}]_{0}^{e}

Compute the boundaries:

\frac{e ^{2}}{2}

= in \frac{e ^{2}}{2}

Simplify

= \frac{e ^{2} in}{2}

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What is the integral from 0 to e of inx ?
The integral from 0 to e of inx is (e^2in)/2