What is the integral from 0 to pi of |sin(2x)| ?

The integral from 0 to pi of |sin(2x)| is 2

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integral from 0 to pi of |sin(2x)|

\int_{0}^{π} ∣ sin (2 x) ∣ d x

2

Solution steps

\int_{0}^{π} ∣ sin (2 x) ∣ d x

Eliminate Absolutes

= \int_{0}^{\frac{π}{2}} sin (2 x) d x + \int_{\frac{π}{2}}^{π} - sin (2 x) d x

\int_{0}^{\frac{π}{2}} sin (2 x) d x = 1

\int_{\frac{π}{2}}^{π} - sin (2 x) d x = 1

= 1 + 1

Simplify

= 2

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What is the integral from 0 to pi of |sin(2x)| ?
The integral from 0 to pi of |sin(2x)| is 2