What is the integral from-infinity to x of e^{-x} ?

The integral from-infinity to x of e^{-x} is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-infinity to x of e^{-x}

\int_{- \infty}^{x} e^{- x} d x

diverges

Solution steps

\int_{- \infty}^{x} e^{- x} d x

Compute the indefinite integral:

\int e^{- x} d x = - e^{- x} + C

Compute the boundaries:

\int_{- \infty}^{x} e^{- x} d x =

diverges

= diverges

\int_{2}^{\infty} u e^{- u} d u

\int_{0}^{3} \frac{1}{3} x^{2} d x

\int_{0}^{2} (x^{4}) d x

\int_{0}^{4} \frac{1}{( x - 2 ) ^{3}} d x

\int_{0}^{5} z e^{- z} d z

What is the integral from-infinity to x of e^{-x} ?
The integral from-infinity to x of e^{-x} is diverges