What is the integral from-1 to 1 of x^3(4+x^4)^3 ?

The integral from-1 to 1 of x^3(4+x^4)^3 is 0

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integral from-1 to 1 of x^3(4+x^4)^3

\int_{- 1}^{1} x^{3} (4 + x^{4})^{3} d x

0

Solution steps

\int_{- 1}^{1} x^{3} (4 + x^{4})^{3} d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

x^{3} (4 + x^{4})^{3} :

Odd

= 0

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\int_{- a}^{a} \frac{3}{1 + x ^{2}} d x

\int_{0}^{4} (6 t - 3) d t

\int_{2}^{3} 4 d x

\int_{- 1}^{1} 6 x d x

What is the integral from-1 to 1 of x^3(4+x^4)^3 ?
The integral from-1 to 1 of x^3(4+x^4)^3 is 0