What is the integral from 1 to 9 of 6sqrt(u) ?

The integral from 1 to 9 of 6sqrt(u) is 104

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integral from 1 to 9 of 6sqrt(u)

\int_{1}^{9} 6 u d u

104

Solution steps

\int_{1}^{9} 6 u d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{1}^{9} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{1}^{9}

= 6 [\frac{2}{3} u^{\frac{3}{2}}]_{1}^{9}

Compute the boundaries:

\frac{52}{3}

= 6 \cdot \frac{52}{3}

Simplify

= 104

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What is the integral from 1 to 9 of 6sqrt(u) ?
The integral from 1 to 9 of 6sqrt(u) is 104