What is the integral from 0 to 16 of 3sqrt(x) ?

The integral from 0 to 16 of 3sqrt(x) is 128

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integral from 0 to 16 of 3sqrt(x)

\int_{0}^{16} 3 x d x

128

Solution steps

\int_{0}^{16} 3 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{16} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{16}

= 3 [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{16}

Compute the boundaries:

\frac{128}{3}

= 3 \cdot \frac{128}{3}

Simplify

= 128

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What is the integral from 0 to 16 of 3sqrt(x) ?
The integral from 0 to 16 of 3sqrt(x) is 128