What is the integral from 0 to 22pi of sin(x) ?

The integral from 0 to 22pi of sin(x) is 0

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integral from 0 to 22pi of sin(x)

\int_{0}^{22 π} sin (x) d x

0

Solution steps

\int_{0}^{22 π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{22 π}

Compute the boundaries:

0

= 0

\int_{0}^{x} (x + 8 y) d y

\int_{0}^{1} (9 - 8 x^{3} + 16 x^{7}) d x

\int_{0}^{π} 36 sin (x) d x

\int_{- \frac{1}{2}}^{\frac{1}{2}} 0.75 (1 - x^{2}) d x

\int_{- 8}^{4} - x^{2} - 3 x d x

What is the integral from 0 to 22pi of sin(x) ?
The integral from 0 to 22pi of sin(x) is 0