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Popular >

integral from-2 to 2 of (t^2-4)

Solution

\int_{- 2}^{2} (t^{2} - 4) d t

Solution

- \frac{32}{3}

+1

Decimal

- 10.66666 \dots

Solution steps

\int_{- 2}^{2} t^{2} - 4 d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{2} t^{2} d t - \int_{- 2}^{2} 4 d t

\int_{- 2}^{2} t^{2} d t = \frac{16}{3}

\int_{- 2}^{2} 4 d t = 16

= \frac{16}{3} - 16

Simplify

\frac{16}{3} - 16 : - \frac{32}{3}

= - \frac{32}{3}

Graph

Popular Examples

integral from 1 to 3 of (x-2)^3

\int_{1}^{3} (x - 2)^{3} d x

integral from 0 to infinity of e^{-yx}

\int_{0}^{\infty} e^{- y x} d x

integral from 0 to 2 of x(2)

\int_{0}^{2} x (2) d x

integral from 2 to 4 of (2x+4)^4

\int_{2}^{4} (2 x + 4)^{4} d x

integral from-3 to-1 of x-4

\int_{- 3}^{- 1} x - 4 d x

Frequently Asked Questions (FAQ)

What is the integral from-2 to 2 of (t^2-4) ?
The integral from-2 to 2 of (t^2-4) is -32/3