What is the integral from 0 to 4pi of cos(x) ?

The integral from 0 to 4pi of cos(x) is 0

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integral from 0 to 4pi of cos(x)

\int_{0}^{4 π} cos (x) d x

0

Solution steps

\int_{0}^{4 π} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= [sin (x)]_{0}^{4 π}

Compute the boundaries:

0

= 0

\int_{0}^{x} sin (x - t) sin (t) d t

\int_{0}^{0.5} ln (1 + x^{4}) d x

\int_{1}^{2} (3 x^{2} + x) d x

\int_{- 1}^{2} \frac{sin ( x )}{x} d x

\int_{0}^{1} \frac{x}{2 x ^{2} + 2} d x

What is the integral from 0 to 4pi of cos(x) ?
The integral from 0 to 4pi of cos(x) is 0