What is the integral from-pi to 0 of sin(θ) ?

The integral from-pi to 0 of sin(θ) is -2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-pi to 0 of sin(θ)

\int_{- π}^{0} sin (θ) d θ

- 2

Solution steps

\int_{- π}^{0} sin (θ) d θ

Use the common integral:

\int sin (θ) d θ = - cos (θ)

= [- cos (θ)]_{- π}^{0}

Compute the boundaries:

- 2

= - 2

\int_{1}^{3} (\frac{9}{13} x^{2} - 2) d x

\int_{1}^{3} \frac{x ^{3}}{3} + \frac{1}{4 x} d x

\int_{0}^{1} (3 x + 4) e^{2 x} d x

\int_{- 3}^{1} 2 x - 3 d x

\int_{- 4}^{2} 8 - 2 x - x^{2} d x

What is the integral from-pi to 0 of sin(θ) ?
The integral from-pi to 0 of sin(θ) is -2