What is the first derivative of y=3x-2 ?

The first derivative of y=3x-2 is 3

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derivative of y=3x-2

derivative of

y = 3 x - 2

3

Solution steps

\frac{d}{d x} (3 x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) - \frac{d}{d x} (2)

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2) = 0

= 3 - 0

Simplify

= 3

y^{^{''}} + 6 y^{^{'}} + 34 y = 0

x \to 0 lim (\frac{5 x ^{3}}{x})

\frac{1}{4} x^{2}, 2 x^{2}, x - 3

\frac{\partial}{\partial x} (6 x (x^{2} + y^{2} + z^{2})^{2})

\int \frac{( 2 x ^{2} + 2 )}{( x ^{2} - 2 x + 2 ) ^{2}} d x