What is the integral from 0 to 4 of (x^2+6x) ?

The integral from 0 to 4 of (x^2+6x) is 208/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 4 of (x^2+6x)

\int_{0}^{4} (x^{2} + 6 x) d x

\frac{208}{3}

Decimal

69.33333 \dots

Solution steps

\int_{0}^{4} x^{2} + 6 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} x^{2} d x + \int_{0}^{4} 6 x d x

\int_{0}^{4} x^{2} d x = \frac{64}{3}

\int_{0}^{4} 6 x d x = 48

= \frac{64}{3} + 48

Simplify

\frac{64}{3} + 48 : \frac{208}{3}

= \frac{208}{3}

\int_{- 0.5}^{0} b + 2 b x d x

\int_{- 1}^{1} (x^{5} - 4 x^{2} + x - 1) d x

\int_{0}^{1} t^{2} + t d t

\int_{1}^{2} t \frac{1}{2} t^{2} + 6 d t

\int_{0}^{7} 2 x d x

What is the integral from 0 to 4 of (x^2+6x) ?
The integral from 0 to 4 of (x^2+6x) is 208/3