What is the integral from 0 to 1 of x^{1/5}-x ?

The integral from 0 to 1 of x^{1/5}-x is 1/3

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integral from 0 to 1 of x^{1/5}-x

\int_{0}^{1} x^{\frac{1}{5}} - x d x

\frac{1}{3}

Decimal

0.33333 \dots

Solution steps

\int_{0}^{1} x^{\frac{1}{5}} - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x^{\frac{1}{5}} d x - \int_{0}^{1} x d x

\int_{0}^{1} x^{\frac{1}{5}} d x = \frac{5}{6}

\int_{0}^{1} x d x = \frac{1}{2}

= \frac{5}{6} - \frac{1}{2}

Simplify

\frac{5}{6} - \frac{1}{2} : \frac{1}{3}

= \frac{1}{3}

\int_{0}^{1} x 45 x^{2} + 36 d x

\int_{0}^{\frac{4}{5}} \frac{1}{25 x ^{2} + 16} d x

\int_{0}^{2} \frac{1}{( x + 4 ) ^{3}} d x

\int_{0}^{1} 1 - z^{2} d z

\int_{0}^{4} (3 - x) d x

What is the integral from 0 to 1 of x^{1/5}-x ?
The integral from 0 to 1 of x^{1/5}-x is 1/3