What is the integral from-1 to 2 of [(x+2)-(x^2)] ?

The integral from-1 to 2 of [(x+2)-(x^2)] is 9/2

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integral from-1 to 2 of [(x+2)-(x^2)]

\int_{- 1}^{2} [(x + 2) - (x^{2})] d x

\frac{9}{2}

Decimal

4.5

Solution steps

\int_{- 1}^{2} x + 2 - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} x d x + \int_{- 1}^{2} 2 d x - \int_{- 1}^{2} x^{2} d x

\int_{- 1}^{2} x d x = \frac{3}{2}

\int_{- 1}^{2} 2 d x = 6

\int_{- 1}^{2} x^{2} d x = 3

= \frac{3}{2} + 6 - 3

Simplify

\frac{3}{2} + 6 - 3 : \frac{9}{2}

= \frac{9}{2}

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What is the integral from-1 to 2 of [(x+2)-(x^2)] ?
The integral from-1 to 2 of [(x+2)-(x^2)] is 9/2