What is the derivative of ln(x+1-e^{3x}) ?

The derivative of ln(x+1-e^{3x}) is 1/(x+1)-e^{3x}*3

What is the first derivative of ln(x+1-e^{3x}) ?

The first derivative of ln(x+1-e^{3x}) is 1/(x+1)-e^{3x}*3

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\frac{d}{d x} (ln (x + 1) - e^{3 x})

\frac{1}{x + 1} - e^{3 x} \cdot 3

Solution steps

\frac{d}{d x} (ln (x + 1) - e^{3 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (ln (x + 1)) - \frac{d}{d x} (e^{3 x})

\frac{d}{d x} (ln (x + 1)) = \frac{1}{x + 1}

\frac{d}{d x} (e^{3 x}) = e^{3 x} \cdot 3

= \frac{1}{x + 1} - e^{3 x} \cdot 3

f (x) = x^{2} + 9, (- 4, 25)

\int \frac{1}{( 1 - x ) ^{4}} d x

\frac{\partial}{\partial x} (8 e^{y x} - x^{2} y^{3})

\int 10 e^{- 10 x} d x

What is the derivative of ln(x+1-e^{3x}) ?
The derivative of ln(x+1-e^{3x}) is 1/(x+1)-e^{3x}*3
What is the first derivative of ln(x+1-e^{3x}) ?
The first derivative of ln(x+1-e^{3x}) is 1/(x+1)-e^{3x}*3