What is the derivative of e^x+e^{-3x} ?

The derivative of e^x+e^{-3x} is e^x-3e^{-3x}

What is the first derivative of e^x+e^{-3x} ?

The first derivative of e^x+e^{-3x} is e^x-3e^{-3x}

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\frac{d}{d x} (e^{x} + e^{- 3 x})

e^{x} - 3 e^{- 3 x}

Solution steps

\frac{d}{d x} (e^{x} + e^{- 3 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) + \frac{d}{d x} (e^{- 3 x})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (e^{- 3 x}) = - 3 e^{- 3 x}

= e^{x} - 3 e^{- 3 x}

\frac{2 \cdot d y}{d x} + 100 \cdot y = 30 \cdot sin (60 x), y (0) = 0

\frac{d}{d x} (sin (2 x) + 3 cos (2 x))

8 x y^{^{'}} = 2 x e^{x} - 8 y + 6 x^{2}

h \to 0 lim (\frac{( - 5 + h ) - 25}{h})

x \to \infty lim ((i)^{x})

What is the derivative of e^x+e^{-3x} ?
The derivative of e^x+e^{-3x} is e^x-3e^{-3x}
What is the first derivative of e^x+e^{-3x} ?
The first derivative of e^x+e^{-3x} is e^x-3e^{-3x}