What is the limit as h approaches 0 of ((-5+h)-25)/h ?

The limit as h approaches 0 of ((-5+h)-25)/h is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as h approaches 0 of ((-5+h)-25)/h

h \to 0 lim (\frac{( - 5 + h ) - 25}{h})

diverges

Solution steps

h \to 0 lim (\frac{- 5 + h - 25}{h})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

h \to 0 + lim (\frac{- 5 + h - 25}{h}) = - \infty

h \to 0 - lim (\frac{- 5 + h - 25}{h}) = \infty

= diverges

x \to \infty lim ((i)^{x})

\int \frac{x ^{2}}{( 2 - x ^{3} ) ^{2}} d x

\frac{d}{d x} (x^{2} + 64)

\frac{\partial}{\partial z} (- 3 e^{x} cos (yz))

\int \frac{5 + 3 x}{1 + x ^{2}} d x

What is the limit as h approaches 0 of ((-5+h)-25)/h ?
The limit as h approaches 0 of ((-5+h)-25)/h is diverges