What is the derivative of sqrt(x^2+64) ?

The derivative of sqrt(x^2+64) is x/(sqrt(x^2+64))

What is the first derivative of sqrt(x^2+64) ?

The first derivative of sqrt(x^2+64) is x/(sqrt(x^2+64))

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\frac{d}{d x} (x^{2} + 64)

\frac{x}{x ^{2} + 64}

Solution steps

\frac{d}{d x} (x^{2} + 64)

Apply the chain rule:

\frac{1}{2 x ^{2} + 64} \frac{d}{d x} (x^{2} + 64)

= \frac{1}{2 x ^{2} + 64} \frac{d}{d x} (x^{2} + 64)

\frac{d}{d x} (x^{2} + 64) = 2 x

= \frac{1}{2 x ^{2} + 64} \cdot 2 x

Simplify

\frac{1}{2 x ^{2} + 64} \cdot 2 x : \frac{x}{x ^{2} + 64}

= \frac{x}{x ^{2} + 64}

\frac{\partial}{\partial z} (- 3 e^{x} cos (yz))

\int \frac{5 + 3 x}{1 + x ^{2}} d x

\int 15 x + 1 d x

e^{x} y \frac{d y}{d x} = 1

y = \frac{2}{x}, (- 2, - 1)

What is the derivative of sqrt(x^2+64) ?
The derivative of sqrt(x^2+64) is x/(sqrt(x^2+64))
What is the first derivative of sqrt(x^2+64) ?
The first derivative of sqrt(x^2+64) is x/(sqrt(x^2+64))