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Popular >

integral from 0 to 1 of y^2-y^3

Solution

\int_{0}^{1} y^{2} - y^{3} d y

Solution

\frac{1}{12}

+1

Decimal

0.08333 \dots

Solution steps

\int_{0}^{1} y^{2} - y^{3} d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} y^{2} d y - \int_{0}^{1} y^{3} d y

\int_{0}^{1} y^{2} d y = \frac{1}{3}

\int_{0}^{1} y^{3} d y = \frac{1}{4}

= \frac{1}{3} - \frac{1}{4}

Simplify

\frac{1}{3} - \frac{1}{4} : \frac{1}{12}

= \frac{1}{12}

Graph

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\int_{1}^{16} x^{- \frac{9}{4}} d x

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of y^2-y^3 ?
The integral from 0 to 1 of y^2-y^3 is 1/12