What is the integral from 1 to 16 of x^{-9/4} ?

The integral from 1 to 16 of x^{-9/4} is 31/40

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 16 of x^{-9/4}

\int_{1}^{16} x^{- \frac{9}{4}} d x

\frac{31}{40}

Decimal

0.775

Solution steps

\int_{1}^{16} x^{- \frac{9}{4}} d x

Apply the Power Rule

: [- \frac{4}{5 x ^{\frac{5}{4}}}]_{1}^{16}

= [- \frac{4}{5 x ^{\frac{5}{4}}}]_{1}^{16}

Compute the boundaries:

\frac{31}{40}

= \frac{31}{40}

\int_{1}^{3 x - 1} \frac{f ( t )}{t} d t

\int_{- 2}^{5} (x^{2} - 3 x + 3) d x

\int_{- 3}^{0} \frac{1}{( x - 1 ) ^{2}} d x

\int_{- 6}^{3} - \frac{1}{x ^{4}} d x

\int_{0}^{2 π} 2 sin (θ) cos (θ) d θ

What is the integral from 1 to 16 of x^{-9/4} ?
The integral from 1 to 16 of x^{-9/4} is 31/40