What is the integral from-3 to 0 of 1/((x-1)^2) ?

The integral from-3 to 0 of 1/((x-1)^2) is 3/4

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integral from-3 to 0 of 1/((x-1)^2)

\int_{- 3}^{0} \frac{1}{( x - 1 ) ^{2}} d x

\frac{3}{4}

Decimal

0.75

Solution steps

\int_{- 3}^{0} \frac{1}{( x - 1 ) ^{2}} d x

Apply u-substitution

: \int_{- 4}^{- 1} \frac{1}{u ^{2}} d u

= \int_{- 4}^{- 1} \frac{1}{u ^{2}} d u

Apply the Power Rule

: [- \frac{1}{u}]_{- 4}^{- 1}

= [- \frac{1}{u}]_{- 4}^{- 1}

Compute the boundaries:

\frac{3}{4}

= \frac{3}{4}

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What is the integral from-3 to 0 of 1/((x-1)^2) ?
The integral from-3 to 0 of 1/((x-1)^2) is 3/4