2yln(x)ln(y)dx+dy=0

解答

2 y ln (x) ln (y) d x + d y = 0

y = e^{e^{2 x + c_{1}} x^{- 2 x}}

求解步骤

2 y ln (x) ln (y) d x + d y = 0

求解可分离方程:

y = e^{e^{2 x + c_{1}} x^{- 2 x}}

y = e^{e^{2 x + c_{1}} x^{- 2 x}}

d er i v a t i v e (4 - 2 x^{2})^{3}

x^{^{'''}} + x^{^{''}} = 0

\int \frac{( x ^{2} + 1 )}{( x ^{2} - 2 x + 2 ) ^{2}} d x

\int sin^{2} (5 x) cos^{2} (5 x) d x

d er i v a t i v e (t + 1)^{\frac{2}{3}} (3 t^{2} - 2)^{3}