What is the integral from 0 to 0.1 of 600x ?

The integral from 0 to 0.1 of 600x is 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 0.1 of 600x

\int_{0}^{0.1} 600 x d x

3

Solution steps

\int_{0}^{0.1} 600 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 600 \cdot \int_{0}^{0.1} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{0.1}

= 600 [\frac{x ^{2}}{2}]_{0}^{0.1}

Simplify

= 600 [0.5 x^{2}]_{0}^{0.1}

Compute the boundaries:

0.005

= 600 \cdot 0.005

Simplify

= 3

\int_{0}^{1} 4 t^{3} sin (t^{4}) d t

\int_{3}^{6} g (x) d x

\int_{0}^{4} \frac{e ^{x}}{10 + e ^{x}} d x

\int_{- 1}^{0} 4 d x

\int_{\frac{π}{6}}^{\frac{π}{4}} sin (t) d t

What is the integral from 0 to 0.1 of 600x ?
The integral from 0 to 0.1 of 600x is 3