What is the integral from pi/6 to pi/4 of sin(t) ?

The integral from pi/6 to pi/4 of sin(t) is -1/(sqrt(2))+(sqrt(3))/2

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integral from pi/6 to pi/4 of sin(t)

\int_{\frac{π}{6}}^{\frac{π}{4}} sin (t) d t

- \frac{1}{2} + \frac{3}{2}

Decimal Notation

0.15891 \dots

Solution steps

\int_{\frac{π}{6}}^{\frac{π}{4}} sin (t) d t

Use the common integral:

\int sin (t) d t = - cos (t)

= [- cos (t)]_{\frac{π}{6}}^{\frac{π}{4}}

Compute the boundaries:

- \frac{1}{2} + \frac{3}{2}

= - \frac{1}{2} + \frac{3}{2}

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What is the integral from pi/6 to pi/4 of sin(t) ?
The integral from pi/6 to pi/4 of sin(t) is -1/(sqrt(2))+(sqrt(3))/2