What is the integral from 0 to 1 of 2e^{x/7}+5 ?

The integral from 0 to 1 of 2e^{x/7}+5 is 14\sqrt[7]{e}-9

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integral from 0 to 1 of 2e^{x/7}+5

\int_{0}^{1} 2 e^{\frac{x}{7}} + 5 d x

Decimal Notation

7.14990 \dots

Solution steps

\int_{0}^{1} 2 e^{\frac{x}{7}} + 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 2 e^{\frac{x}{7}} d x + \int_{0}^{1} 5 d x

\int_{0}^{1} 5 d x = 5

Simplify

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\int_{3}^{5} 25 - x^{2} d x

\int_{0.5}^{1} 3 e^{- 3 x} d x

What is the integral from 0 to 1 of 2e^{x/7}+5 ?
The integral from 0 to 1 of 2e^{x/7}+5 is 14\sqrt[7]{e}-9