What is the integral from x to x^2 of cos(t) ?

The integral from x to x^2 of cos(t) is sin(x^2)-sin(x)

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integral from x to x^2 of cos(t)

\int_{x}^{x^{2}} cos (t) d t

sin (x^{2}) - sin (x)

Solution steps

\int_{x}^{x^{2}} cos (t) d t

Use the common integral:

\int cos (t) d t = sin (t)

= [sin (t)]_{x}^{x^{2}}

Compute the boundaries:

sin (x^{2}) - sin (x)

= sin (x^{2}) - sin (x)

\int_{2}^{4} - \frac{6}{x ^{2}} d x

\int_{0}^{\frac{a}{2}} sin^{2} (\frac{π x}{a}) d x

\int_{- 2}^{1} 3 + y^{2} d y

\int_{\frac{π}{6}}^{\frac{π}{4}} sin (4 t) d t

\int_{0}^{8} 9 e^{x} d x

What is the integral from x to x^2 of cos(t) ?
The integral from x to x^2 of cos(t) is sin(x^2)-sin(x)