What is the solution for (dy)/(dx)=3x^2(y-1)^3 ?

The solution for (dy)/(dx)=3x^2(y-1)^3 is y=sqrt(-1/(2(x^3+c_{1)))}+1,y=-sqrt(-1/(2(x^3+c_{1)))}+1

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(dy)/(dx)=3x^2(y-1)^3

\frac{d y}{d x} = 3 x^{2} (y - 1)^{3}

y = - \frac{1}{2 ( x ^{3} + c _{1} )} + 1, y = - - \frac{1}{2 ( x ^{3} + c _{1} )} + 1

Solution steps

\frac{d y}{d x} = 3 x^{2} (y - 1)^{3}

Solve separable ODE:

y = - \frac{1}{2 ( x ^{3} + c _{1} )} + 1, y = - - \frac{1}{2 ( x ^{3} + c _{1} )} + 1

y = - \frac{1}{2 ( x ^{3} + c _{1} )} + 1, y = - - \frac{1}{2 ( x ^{3} + c _{1} )} + 1

\frac{d}{d x} (2 (x - 2)^{2})

sin^{2} (2 t)

\int ln (x - 3) d x

f (x) = \frac{2}{x - 5}, at x = 7

\int (x^{2} + 1) (4 x - 3) d x

What is the solution for (dy)/(dx)=3x^2(y-1)^3 ?
The solution for (dy)/(dx)=3x^2(y-1)^3 is y=sqrt(-1/(2(x^3+c_{1)))}+1,y=-sqrt(-1/(2(x^3+c_{1)))}+1