What is the integral from-1 to 2 of (x^3+e^{1/4 x}) ?

The integral from-1 to 2 of (x^3+e^{1/4 x}) is 15/4+4(sqrt(e)-1/(\sqrt[4]{e)})

Popular >

integral from-1 to 2 of (x^3+e^{1/4 x})

\int_{- 1}^{2} (x^{3} + e^{\frac{1}{4} x}) d x

\frac{15}{4} + 4 (e - \frac{1}{4 e})

Decimal

7.22968 \dots

Solution steps

\int_{- 1}^{2} x^{3} + e^{\frac{1}{4} x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} x^{3} d x + \int_{- 1}^{2} e^{\frac{1}{4} x} d x

\int_{- 1}^{2} x^{3} d x = \frac{15}{4}

\int_{- 1}^{2} e^{\frac{1}{4} x} d x = 4 (e - \frac{1}{4 e})

= \frac{15}{4} + 4 (e - \frac{1}{4 e})

\int_{0}^{\infty} e^{- 0.1 t} d t

\int_{2}^{5} x^{4} - 2 x d x

\int_{1}^{2} (3 x^{2} + 3) d x

\int_{0}^{3} (8 x - 2 x^{3}) d x

\int_{0}^{1} \frac{3}{x ^{4}} d x

What is the integral from-1 to 2 of (x^3+e^{1/4 x}) ?
The integral from-1 to 2 of (x^3+e^{1/4 x}) is 15/4+4(sqrt(e)-1/(\sqrt[4]{e)})