What is the derivative of x^2-2x-3 ?

The derivative of x^2-2x-3 is 2x-2

What is the first derivative of x^2-2x-3 ?

The first derivative of x^2-2x-3 is 2x-2

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\frac{d}{d x} (x^{2} - 2 x - 3)

2 x - 2

Solution steps

\frac{d}{d x} (x^{2} - 2 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (2 x) - \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (3) = 0

= 2 x - 2 - 0

Simplify

= 2 x - 2

x \to 0 lim (\frac{sin ( m x )}{x})

\int x^{3} + 2 x^{2} - 3 x d x

y^{^{'}} = 3 + t - y

\frac{d}{d x} (10 e^{- x})

\frac{\partial}{\partial x} (ln (4 x^{2}))

What is the derivative of x^2-2x-3 ?
The derivative of x^2-2x-3 is 2x-2
What is the first derivative of x^2-2x-3 ?
The first derivative of x^2-2x-3 is 2x-2